Directions How to Answer

Aptitude Test Topic: Functions

Functions include Linear functions and Graphical functions.

Directions

Solve the given question and choose the best answer from the given choices.

To give the answer click/tap the option alphabet for your answer choice. for correct answer green check and for wrong answer a red cross will appear along with a button to show explanation with or without video of the question answer.

Functions: Graphing Functions Practice MCQ

Question Statement:

Transform the following parabola $y = (x - 6)^{2} + 5$

Move 5 units to the left.

Move 1 unit down.

y = (x - 1)^{2} + 4

y = (x)^{6} + 9

y = (x + 6)^{2} - 5

y = (x - 11)^{2} + 9

y = (x + 11)^{2} - 9

Explanation:

Correct Answer: A

To move unit down, subtract from Y (or from the entire equation) , so subtract 1.

To move unit to the left, add to X (don't forget, that since you are squaring X, you must square the addition as well).

With the move down our equation $y = (x - 6)^{2} + 5$ becomes $y = (x - 6)^{2} + 5 - 1 = (x - 6)^{2} + 4$

Now to move it to the left we get $y = (x - 6 + 5)^{2} + 4 = (x - 1)^{2} + 4$

Question: 4 Test: 3 of 4 Next Test

Tests

You are taking Aptitude Test No. 3

Each aptitude test is comprised of 10 except the last test which might have fewer than 10 in some topics.

You are at question (MCQ) number 4 and Test Number 3 of Functions: Graphing Functions. To deal with Functions questions, you must take lesson on the subject. In case of science and Art subjects revise your text books and in case of general aptitude topics take lessons from the topic page.

The question:

Transform the following parabola $y = (x - 1)^{2} + 4$ , $y = (x)^{6} + 9$ , $y = (x + 6)^{2} - 5$ , $y = (x - 11)^{2} + 9$ can be solved with the concepts and understanding of Functions.