The slope of the line for the graph of log k vs l/T for the reaction, N2O5 → 2NO2+ ½ O2 is -5000. Calculate the energy of activation of the reaction.
Slope=Ea/2.303R Ea = - slope × 2.303 R = - (-5000) × 2.303 × 8.314 = 95700 JK-1 mol-1 =95.7 kJ K-1 mol-1
645 MCQ for effective preparation of the test of Basics of Chemistry section.
Read the MCQ statement: The slope of the line for the graph of log k vs l/T for the reaction, N2O5 → 2NO2+ ½ O2 is -5000. Calculate the energy of activation of the reaction. , keenly and apply the method you have learn through the video lessons for Basics to give the answer. Record your answer and check its correct answer and video explanation for MCQ No. 272-2458.