The enthalpy change (∆H) for the reaction N2(g) + 2H2(g)→2NH3(g)is -92.38 KJ at 298 K is
The enthalpy change (∆H) for the reaction for N2(g) + 2H2(g)→2NH3(g) is -92.38 KJ at 298 In the above reaction two moles of ammonia are formed, ∆H will be half for 1 mole.
645 MCQ for effective preparation of the test of Basics of Chemistry section.
Read the MCQ statement: The enthalpy change (∆H) for the reaction N2(g) + 2H2(g)→2NH3(g)is -92.38 KJ at 298 K is , keenly and apply the method you have learn through the video lessons for Basics to give the answer. Record your answer and check its correct answer and video explanation for MCQ No. 286-2472.