Subject - Chemistry:

Basics

MCQ - 382-2568

Question:

The density of a solution prepared by dissolving 120 g of urea (mol.mass = 60 u) in 1000 g of water is 1.15 g/mL. The molarity of this solution is:

1.02 M
2.05 M
0.50 M
2.05 M

Correct Answer: B

Explanation:

The correct option is '2'.
Molarity of a solution (M) = n/V
Where: n = number of moles of urea = 120/60 = 2 mol
V = volume of the solution = mass of solution / density of solution
= (120 + 1000) g / 1.15 g mL^-1 = 974 mL = 0.974 L
Therefore: M = 2 mol / 0.974 L = 2.05 mol L^-1
Note: Volume of solution should be expressed in litres.

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645 MCQ for effective preparation of the test of Basics of Chemistry section.

Read the MCQ statement: The density of a solution prepared by dissolving 120 g of urea (mol.mass = 60 u) in 1000 g of water is 1.15 g/mL. The molarity of this solution is: , keenly and apply the method you have learn through the video lessons for Basics to give the answer. Record your answer and check its correct answer and video explanation for MCQ No. 382-2568.

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Solve the question for MCQ No. and decide which option (A through D/E) is the best choice to answer the MCQ, then click/tap the blue button to view the correct answer and it explanation.

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