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Subject - Chemistry:

Basics

MCQ - 509-2695

Question:

The isoneutronic group, in the following, is:

  1. 6C12, 7N14, 8O16
  2. 6C12, 7N14, 8O18
  3. 6C14, 7N14, 8O16
  4. 6C12, 7N14, 8O18

Correct Answer: D

Explanation:

Two nuclides are isoneutronic (isotones) if they have the very same neutron number As per the question 6C14 = 14 – 6 = 8 neutron 7C15 = 15–7 = 8 neutron 8C16 = 16 – 8 = neutron Since the number of neutrons in all is 8 they are all Isotones.

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