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Non Verbal Reasoning - Coding and Decoding:

Coding Decoding

MCQ - 163-8492

Question:

If FIRE is coded as ‘#*?%’, then FREEZE will be coded as

  1. #&%%?*
  2. ??%%#*
  3. %%%?^^
  4. ??%%#*

Correct Answer: D

Explanation:

Now this is a tricky question. You won’t be able to solve the question, so you have to follow "Options elimination" approach. Now one basic thing to be kept in mind is that FREEZE contains 3 E’s. and as per FIRE code we can assume that any one of the symbols can be for E and so it will be repeated 3 times in the answer. Option a and b are directly eliminated because there is no symbol repeating thrice. Now in option C if we notice, there is a new sign which is ^. So this sign can be for Z. but there is only one Z in FREEZE. So two ^^ are not possible. In option D there are ??? which can be for E. and @ which can be for Z. and rest % # for F and R.

Record Performance

167 MCQ for effective preparation of the test of Coding Decoding of Coding and Decoding section.

Read the MCQ statement: If FIRE is coded as ‘#*?%’, then FREEZE will be coded as, keenly and apply the method you have learn through the video lessons for Coding Decoding to give the answer. Record your answer and check its correct answer and video explanation for MCQ No. 163-8492.

How to Answer

Solve the question for MCQ No. and decide which option (A through D/E) is the best choice to answer the MCQ, then click/tap the blue button to view the correct answer and it explanation.

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