Subject - Mathematics:

General

MCQ - 174-8906

Question:

The foci of the ellipse $\frac{x2}{16}$ + $\frac{y2}{b2}$ = 1 and the hyperbola $\frac{x2}{144}$ - $\frac{y2}{81}$ = $\frac{1}{25}$ coincide, then the value of b² is

Correct Answer: D

Explanation:

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