General

MCQ - 190-8922

Question:

If the normal at [ct, $\frac{c}{t}$ ] on the curve xy = c² meets the curve again in ‘t’, then

t' = - $\frac{1}{t3}$
t' = - $\frac{1}{t}$
t' =- $\frac{1}{t2}$
t' = - $\frac{1}{t}$

Correct Answer: A

Explanation:

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