Subject - Mathematics:

General

MCQ - 367-9099

Question:

The pair of linear equations 4x - 5y - 20 = 0 and 3x + 5y -15 = 0 has

a unique solution
two solutions
many solutions
two solutions

Correct Answer: A

Explanation:

Equation 1: 4x - 5y = 20
Equation 2: 3x + 5y = 15
Both the equations are in the form of :
a¹x + b¹y= c¹ & a²x + b²y = c² where
According to the problem:
a¹ = 4
a² = 3
b¹ = -5
b² = 5
c¹ = 20
c² = 15
We compare the ratios

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