Correct Answer: C
Explanation:
All 2-digit numbers divisible by 6 are as follows: –
6, 12, ………., 96
The above series of numbers forms an arithmetic progression with
first term(a) = 6 and,
common difference(d) = (n + 1)th term – nth term = 12 – 6 = 6
last term or nth term(an) = 96
Let the number of terms in above series be n.
∵ an = a + (n – 1) × d
⇒ 96 = 6 + (n – 1) × 6
⇒ 90 = 6n – 6
⇒ 6n = 96
∴ n = 16
Thus, total no. of all 2-digit numbers divisible by 6.