Correct Answer: A
Explanation:
In Δ PAB,
∠ APB = 60° and PA = 8 cm [given]
∴ PB = PA = 8 cm
[∵ tangents drawn from an exterior point to the circle are equal in length]
⇒ ∠ PAB = ∠ PBA = θ [LET]
Now, In Δ PAB
∠ APB + ∠ PAB + ∠ PBA = 180° [∵ Sum of all the angles of a Δ is 180°]
⇒ 60° + θ + θ = 180°
⇒ 60° + 2θ = 180°
⇒ 2θ = 120°
∴ θ = 60°
Thus, Δ PAB is an equilateral Triangle.
∴ Length of chord AB = 8 cm.