Subject - Mathematics:

General

MCQ - 42-8774

Question:

Compute

22 [\begin{matrix} 7 & 6 & 16 \\ 0 & 0 & 12 \end{matrix}]

$[\begin{matrix} 154 & 0 & 352 \\ 0 & 132 & 264 \end{matrix}]$
$[\begin{matrix} 154 & 132 & - 352 \\ 0 & 0 & - 264 \end{matrix}]$
$[\begin{matrix} 154 & 132 & 352 \\ 0 & 0 & 264 \end{matrix}]$
$[\begin{matrix} 154 & 132 & - 352 \\ 0 & 0 & - 264 \end{matrix}]$

Correct Answer: D

Explanation:

In order to compute this, we need to multiply each entry by the scalar 22.

22 [\begin{matrix} 7 & 6 & 16 \\ 0 & 0 & 12 \end{matrix}] = [\begin{matrix} 22 \cdot 7 & 22 \cdot 6 & 22 \cdot 16 \\ 22 \cdot 0 & 22 \cdot 0 & 22 \cdot 12 \end{matrix}] = [\begin{matrix} 154 & 132 & 352 \\ 0 & 0 & 264 \end{matrix}]

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