If 4, x1, x2, x3, 28 are in AP then x3 = ?
Here, first term = a = 4 Last term = l = 28 Number of terms = n = 5 ∴ l = a + (n - 1)d ⇒ 28 = 4 + (5 - 1)d ⇒ 28 - 4 = 4d ⇒ 4d = 24 ⇒ d = 6 Therefore x3 = a + 3d = 4 + 3(6) = 4 + 18 = 22
504 MCQ for effective preparation of the test of Arithmetic Progression of Mathematics section.
Read the MCQ statement: If 4, x1, x2, x3, 28 are in AP then x3 = ? , keenly and apply the method you have learn through the video lessons for Arithmetic Progression to give the answer. Record your answer and check its correct answer and video explanation for MCQ No. 440-9172.