Correct Answer: D
Explanation:
The three digit numbers divisible by 9 are 108, 117, 126, …., 999.
This forms an AP with first term a = 108
and common difference = d = 9
Last term is 999.
Now, number of terms in this AP are given as:
999 = a + (n - 1)d
⇒ 999 = 108 + (n - 1)9
⇒ 999 - 108 = 9n - 9
⇒ 891 + 9 = 9n
⇒ 900 = 9n
⇒ n = 100
There are 100 three - digit numbers that are divisible by 9.