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Subject - Physics:

Basics

MCQ - 41-10508

Question:

The phenomena of pair production takes place if the energy of photon is greater than?

  1. 1.02 Mew
  2. 1.0 Mew
  3. 0.051 Mew
  4. 1.0 Mew

Correct Answer: A

Explanation:

Conservation of total energy for pair production = hv = E– + E+ = (m0c2 + K–) + (M0c2 + K+) = K- + K+ + 2m0c2
Here, E- and E+ represent total energy of the electron and positron, and K- and K+ represent the kinetic energy of the electron and positron. Also, m0c2 = 0.511 MeV, and it is the rest mass energy of an electron, which is equal to that of the positron. That is, both the two particles have the same amount of rest mass energy, and from this, we can get the sum, 2m0c2 = 1.02 MeV.

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