Correct Answer: A
Explanation:
Answer is A.
in Column A find the roots of the given quadratic equation. An easy method of solution is by factoring. Since the left side of the equation
x2 + 3x + 2 may be factored as (x + 2) (x + 1).
then the equation may be written as
(x + 2)(x + 1) = 0
using the zero factor property (that is, for real numbers a and b, if ab = 0 then a = 0 or b = 0), one can write the last equation as two linear equations and solve each to obtain the roots of the original equation. Thus,
|
x + 2 = 0 |
x + 1 = 0 |
|
x + 2 + (-2) |
x + 1 + (-1) = 0 + (-1) |
|
x + 0 = -2 |
x + 0 = -1 |
|
x = -2 |
x = -1 |
so, the roots of the equation are -2, -1. The product is (-2)(-1) = 2 which is larger than the quantity in Column B.
An easier approach is to recognize that the product of roots of a quadratic equation in standard form ax2 + bx + c = 0 is given by c/a.