Quantitative - Mathematics - Solid Geometry:

Polygons

MCQ - 105-11957

Question:

If the perimeter of a septagon is equal to 5(x²+ 1)+2x(x − 4), what is the length of one side? (All sides of the septagon are equal.)

$7 x^{2} - 4 x + 5$
$x^{2} - \frac{8 x}{7} + \frac{5}{7}$
$x^{2} - 4 x + 5$
$x^{2} - \frac{8 x}{7} + \frac{5}{7}$

Correct Answer: B

Explanation:

If the perimeter of a septagon (in which all sides are equal) is 5(x² + 1) + 2x(x − 4), then the length of one side will be one-seventh of this expression.

To find one seventh, the value must first be simplified and then divided by 7.

$5 (x^{2} + 1) + 2 x (x - 4)$

$5 x^{2} + 5 + 2 x^{2} - 8 x$

$7 x^{2} - 8 x + 5$

When this is divided by 7, the result is:

$x^{2} - \frac{8 x}{7} + \frac{5}{7}$

This value is thus the length of one side of the septagon.

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131 MCQ for effective preparation of the test of Polygons of Solid Geometry section.

Read the MCQ statement: If the perimeter of a septagon is equal to 5(x2+ 1)+2x(x − 4), what is the length of one side? (All sides of the septagon are equal.), keenly and apply the method you have learn through the video lessons for Polygons to give the answer. Record your answer and check its correct answer and video explanation for MCQ No. 105-11957.

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