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Quantitative - Mathematics - Solid Geometry:

Quadrilatorals

MCQ - 110-11962

Question:

Find the perimeter of a rectangle with a width of 8in and a length that is two times the width.

  1. 36in
  2. 24in 16in
  3. 64in
  4. 24in 16in

Correct Answer: D

Explanation:

To find the perimeter of a rectangle, we will use the following formula:

P = 2l + 2w

Where l is the length and w is the width of the rectangle.

Now, we know the width of the rectangle is 8in. We also know the length is two times the width. Therefore, the length is 16in. So, we can substitute. We get

P = 2(16in) + 2(8in)

P = 32in + 16in

P = 48in

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131 MCQ for effective preparation of the test of Quadrilatorals of Solid Geometry section.

Read the MCQ statement: Find the perimeter of a rectangle with a width of 8in and a length that is two times the width., keenly and apply the method you have learn through the video lessons for Quadrilatorals to give the answer. Record your answer and check its correct answer and video explanation for MCQ No. 110-11962.

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Solve the question for MCQ No. and decide which option (A through D/E) is the best choice to answer the MCQ, then click/tap the blue button to view the correct answer and it explanation.

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