In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither blue nor green?
Total number of balls = (8 + 7 + 6) = 21 Let E = event that the ball drawn is neither blue nor green = event that the ball drawn is red. Therefore, n(E) = 8.
Total number of balls = (8 + 7 + 6) = 21
Let E = event that the ball drawn is neither blue nor green = event that the ball drawn is red.
Therefore, n(E) = 8.
1297 MCQ for effective preparation of the test of Probability of Word Problems section.
Read the MCQ statement: In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither blue nor green? , keenly and apply the method you have learn through the video lessons for Probability to give the answer. Record your answer and check its correct answer and video explanation for MCQ No. 138-12905.