Quantitative - Mathematics - Word Problems:

Probability

MCQ - 143-12910

Question:

A box contains 20 electric bulbs, out of which 4 are defective. Two bulbs are chosen at random from this box. The probability that at least one of these is defective is

7/19
6/19
5/19
6/19

Correct Answer: A

Explanation:

Please remember that Maximum portability is 1.

So we can get total probability of non-defective bulbs and subtract it from 1 to get total probability of defective bulbs.

Total cases of non defective bulbs = ¹⁶C₂ = 16 × 152 × 1 = 120

= ²⁰C₂ = $\frac{20 × 19}{2 × 1}$ = 190

= $\frac{120}{190}$ = $\frac{12}{19}$

Probability of at least one defective = 1 − 1 $\frac{12}{19}$ = $\frac{7}{19}$

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1297 MCQ for effective preparation of the test of Probability of Word Problems section.

Read the MCQ statement: A box contains 20 electric bulbs, out of which 4 are defective. Two bulbs are chosen at random from this box. The probability that at least one of the .... is defective is , keenly and apply the method you have learn through the video lessons for Probability to give the answer. Record your answer and check its correct answer and video explanation for MCQ No. 143-12910.

How to Answer

Solve the question for MCQ No. and decide which option (A through D/E) is the best choice to answer the MCQ, then click/tap the blue button to view the correct answer and it explanation.

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