Correct Answer: D
Explanation:
The trio of “1, 2, 3”s will end at the 99th place, and the 100th place must be 1.
So, we have 33 groups of “1, 2, 3”, plus a “1” leftover. There are 33 groups because there are 99 digits in the series divided up into groups of 3 each. 99 ÷ 3 = 33, so there are 33 groups.
33 × (1 + 2 + 3) + 1. = 198 + 1 = 199