If sin 3θ = cos (θ - 2°), where 3θ and (θ - 2°) are both acute angles, then θ = ?
Given, we know that sin θ = cos(90° - θ) Replacing θ by 3θ ⇒ sin(3θ) = cos(90° - 3θ) ⇒ cos(θ - 2°) = cos(90° - 3θ) [ Given, sin 3θ = cos(θ - 2°)] ⇒ θ - 2° = 90° - 3θ ⇒ 4θ = 92° ⇒ θ = 23°
504 MCQ for effective preparation of the test of General of Mathematics section.
Read the MCQ statement: If sin 3θ = cos (θ - 2°), where 3θ and (θ - 2°) are both acute angles, then θ = ? , keenly and apply the method you have learn through the video lessons for General to give the answer. Record your answer and check its correct answer and video explanation for MCQ No. 349-9081.