If tan θ = √3, then
Given, tan θ = √3 ⇒ tan2θ = 3 ⇒ sec2θ - 1 = 3 [As tan2θ + 1 = sec2θ] ⇒ sec2θ = 4 …[1] Also, Squaring both sides, [As cot2θ + 1 = 1/3 cosec2θ = 4/3 …[2] Putting the values from [1] and [2] into given eqn
Given, tan θ = √3 ⇒ tan2θ = 3 ⇒ sec2θ - 1 = 3 [As tan2θ + 1 = sec2θ] ⇒ sec2θ = 4 …[1] Also,
504 MCQ for effective preparation of the test of General of Mathematics section.
Read the MCQ statement: If tan θ = √3, then , keenly and apply the method you have learn through the video lessons for General to give the answer. Record your answer and check its correct answer and video explanation for MCQ No. 350-9082.