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Subject - Mathematics:

General

MCQ - 379-9111

Question:

Find the value of p for which the quadratic equation x2 – 2px + 1 = 0 has no real roots.

  1. -1,1
  2. 2,2
  3. 4,4
  4. 2,2

Correct Answer: A

Explanation:

The given quadratic equation is x2 – 2px + 1 = 0.
And, Discriminant D of the quadratic equation ax2 + bx + c = 0 is given by –
D = b2 – 4ac
Comparing the equation ax2 + bx + c = 0 with given quadratic equation is
x2– 2px + 1 = 0, we get –
a = 1, b = – 2p and, c = 1
∴ D = (– 2p)2 – 4(1)(1) = 4p2 – 4 = 4(p2 – 1)
For no real roots,
D < 0
⇒ 4(p2 – 1) < 0
⇒ p2 – 1 < 0
⇒ (p + 1)(p – 1) < 0
∴ p ∈ (– 1,1)
Thus, p can take any values between – 1 and 1 for no real roots of given quadratic equation.

Record Performance

504 MCQ for effective preparation of the test of General of Mathematics section.

Read the MCQ statement: Find the value of p for which the quadratic equation x2 – 2px + 1 = 0 has no real roots., keenly and apply the method you have learn through the video lessons for General to give the answer. Record your answer and check its correct answer and video explanation for MCQ No. 379-9111.

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