Correct Answer: B
Explanation:
The above series of numbers forms an arithmetic progression with
first term(a) = 4 and,
common difference(d) = (n + 1)th term – nth term = 9 – 4 = 5
last term or nth term(an) = 254
Let the total no. of terms in above A.P be n.
∴ an = a + (n – 1) × d
⇒ 254 = 4 + (n – 1) × 5
⇒ 250 = 5n – 5
⇒ 5n = 255
∴ n = 51
∴ 10th term from the end of AP = 51 – 10 + 1 = 42th term from the beginning
∴ 42th term = a42 = a + (42 – 1)d
= 4 + 41 × 5
= 209
Hence, 10th term from the end of AP is 209.