Correct Answer: C
Explanation:
First 40 positive integers divisible by 6 are 6, 12, 18, …, 240.
Sum of these numbers forms an arithmetic series 6 + 12 + 18 + … + 240.
Here, first term = a = 6
Common difference = d = 6
Sum of n terms of this arithmetic series is given by:
Sn = [2a + (n - 1)d]
Therefore sum of 40 terms of this arithmetic series is given by:
∴ S40 = [2(6) + (40 - 1)(6)]
= 20 [12 + 234]
=20 × 246
= 4920