Correct Answer: B
Explanation:
The two digit numbers divisible by 3 are 12, 15, 18, 21, …., 99.
This forms an AP with first term a = 12
and common difference = d = 3
Last term is 99.
Now, number of terms in this AP are given as:
99 = a + (n - 1)d
⇒ 99 = 12 + (n - 1)3
⇒ 99 - 12 = 3n - 3
⇒ 87 + 3 = 3n
⇒ 90 = 3n
⇒ n = 30
There are 30 two - digit numbers that are divisible by 3