The rest mass of a proton is ‘m0’. Its linear momentum when it moves with half the speed of light ‘c’ in free space is
The mass of the proton while moving with velocity ‘v’ is given by m = m0/√[1- v2/c2] so that when v = c/2, m = m0/√[1- ¼] = 2m0/√3. The momentum of the proton is mc/2 = m0c/√3.
346 MCQ for effective preparation of the test of Basics of Physics section.
Read the MCQ statement: The rest mass of a proton is ‘m0’. Its linear momentum when it moves with half the speed of light ‘c’ in free space is , keenly and apply the method you have learn through the video lessons for Basics to give the answer. Record your answer and check its correct answer and video explanation for MCQ No. 35-10502.