In a nuclear reactor using U235 as fuel the power output is 4.8 megawatts. The number of fissions per second is (energy released per fission of U235 = 200 MeV).
The energy produced per second is 4.8×106 joule. Since 1 electron volt is 1.6×10-19 joule, 200 MeV = 200×106×1.6×10-19 joule. Therefore, The number of fissions per second = (4.8×106)/(200×106×1.6×10-19) = 1.5×1017.
346 MCQ for effective preparation of the test of Basics of Physics section.
Read the MCQ statement: In a nuclear reactor using U235 as fuel the power output is 4.8 megawatts. The number of fissions per second is (energy released per fission of U235 = 200 MeV). , keenly and apply the method you have learn through the video lessons for Basics to give the answer. Record your answer and check its correct answer and video explanation for MCQ No. 36-10503.