Correct Answer: A
Explanation:
From 2 white balls, 3 black balls, and 4 red balls, 3 balls are to be selected such that at least one black ball should be there.
Hence we have 3 choices
Three are black
Two are black and one is non black
One is black and two are non black
Total number of ways = 3C3 + (3C2 x 6C1) + (3C1 x 6C2) [because 6 are non black]
=1+[3×6]+[3×(6××1)]=1+18+45=64