Quantitative - Mathematics - Word Problems:

Permutation and Combinations

MCQ - 162-12929

Question:

A box contains 4 red, 3 white and 2 blue balls. Three balls are drawn at random. Find out the number of ways of selecting the balls of different colors

Correct Answer: B

Explanation:

This question seems to be a bit typical, isn't, but it is simplest.

1 red ball can be selected in ⁴C₁ ways

1 white ball can be selected in ³C₁ ways

1 blue ball can be selected in ²C_{1 ways}

Total number of ways

= ⁴C₁ × ³C₁ × ²C₁

= 4 x 3 x 2

= 24

Please note that we have multiplied the combination

results, we use to add when their is OR condition, and we

use to multiply when there is AND condition, In this

question it is AND as

1 red AND 1 White AND 1 Blue, so we multiplied.

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1297 MCQ for effective preparation of the test of Permutation and Combinations of Word Problems section.

Read the MCQ statement: A box contains 4 red, 3 white and 2 blue balls. Three balls are drawn at random. Find out the number of ways of selecting the balls of different colors , keenly and apply the method you have learn through the video lessons for Permutation and Combinations to give the answer. Record your answer and check its correct answer and video explanation for MCQ No. 162-12929.

How to Answer

Solve the question for MCQ No. and decide which option (A through D/E) is the best choice to answer the MCQ, then click/tap the blue button to view the correct answer and it explanation.

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